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dryte
@dryte
July 2022
2
28
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Решите уравнение
sin^2x+7 sin x+6=0
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adik61
sin
²
x+7*sinx+6=0
пусть sinx=t, |t|
≤1
t²+7t+6=0
по теореме Виета
t=-1
t=-6(посто кор)
sinx=-1
x=-π/2 + 2πn (n∈Z)
1 votes
Thanks 2
ПрофиЗнания
Sinx=t
t²+7t+6=0
D=49-4*6*1=49-24=25=5²
t1=-7+5/2=-2/2=-1
t2=-7-5/2=-12/2=-6 не подходит
sinx=-1
x=-p/2 +2pn n∈z
1 votes
Thanks 0
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Answers & Comments
пусть sinx=t, |t|≤1
t²+7t+6=0
по теореме Виета
t=-1
t=-6(посто кор)
sinx=-1
x=-π/2 + 2πn (n∈Z)
t²+7t+6=0
D=49-4*6*1=49-24=25=5²
t1=-7+5/2=-2/2=-1
t2=-7-5/2=-12/2=-6 не подходит
sinx=-1
x=-p/2 +2pn n∈z