Решите уравнение:(^- степень)
(a^2-9)x=7a^2-20a-3
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х=7а²-20а-3/а²-9
7а²-20а-3=0
D=400+4*7*3=400+84=484
√D=22
а₁=20+22/14=42/14=3
а₂=20-22/14=-2/14=-1/7
7а²-20а-3=7(а-3)(а+1/7)
х=7а²-20а-3/а²-9 =7(а-3)(а+1/7)/а²-9=7(а-3)(а+1/7)/(а-3)(а+3)=7(а+1/7)/(а+3)=7а+1/а+3