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evgeniykaliansk
@evgeniykaliansk
July 2022
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Решите уравнение:
(x - 2)^2 + 3x - 6 - 5( 2 - x) = 0
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Pacanka202
Х^2–4х+4+3х–6–10+5х=0
х^2+4х–12=0
Д=/16–4•1•(-12)=/64=8
х1=(-4+8)/2=2
х2=(-4-8)/2=-6
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Answers & Comments
х^2+4х–12=0
Д=/16–4•1•(-12)=/64=8
х1=(-4+8)/2=2
х2=(-4-8)/2=-6