(x-2)(x^2+2x+1)=4(x+1)
(x-2)(x+1)(x+1)-4(x+1) = 0
(x+1)*((x-2)(x+1) - 4) = 0
(x+1)*(x^2 - 2x + x - 2 - 4) = 0
(x + 1)(x^2 - x - 6) = 0 {D=1+24 = 25 x12=(1 +- 5)/2 = 3 -2}
(x + 1)(x + 2)(x - 3) = 0
x1 = -1
x2 = -2
x3 = 3
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(x-2)(x^2+2x+1)=4(x+1)
(x-2)(x+1)(x+1)-4(x+1) = 0
(x+1)*((x-2)(x+1) - 4) = 0
(x+1)*(x^2 - 2x + x - 2 - 4) = 0
(x + 1)(x^2 - x - 6) = 0 {D=1+24 = 25 x12=(1 +- 5)/2 = 3 -2}
(x + 1)(x + 2)(x - 3) = 0
x1 = -1
x2 = -2
x3 = 3
Відповідь:
Пояснення: