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belyc
@belyc
July 2022
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Решите уравнение (x-4)^2*(2x-3)=(2x-3)^2*(x-4)
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tlq
(x-4)
²
*(2x-3)=(2x-3)
²
*(x-4)
(x-4)
²(2x-3)-(2x-3)²(x-4)=0
(x-4)(2x-3)(x-4-2x+3)=0
(x-4)(2x-3)(-x-1)=0
x-4=0
2x-3=0
-x-1=0
x3=4
x2=3/2
x1=-1
2 votes
Thanks 1
belyc
Спасибо, а то у меня написано решение похожего,а как решать всё равно понять не могу.
kamila051825
(x-4)²*(2x-3)=(2x-3)²*(x-4)
(x-4)²(2x-3)-(2x-3)²(x-4)=0
(x-4)(2x-3)(x-4-2x+3)=0
(x-4)(2x-3)(-x-1)=0
x-4=0
2x-3=0
-x-1=0
x3=4
x2=3/2
x1=-1
0 votes
Thanks 0
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Answers & Comments
(x-4)²(2x-3)-(2x-3)²(x-4)=0
(x-4)(2x-3)(x-4-2x+3)=0
(x-4)(2x-3)(-x-1)=0
x-4=0
2x-3=0
-x-1=0
x3=4
x2=3/2
x1=-1
(x-4)²(2x-3)-(2x-3)²(x-4)=0
(x-4)(2x-3)(x-4-2x+3)=0
(x-4)(2x-3)(-x-1)=0
x-4=0
2x-3=0
-x-1=0
x3=4
x2=3/2
x1=-1