Решите уравнение: (x^2-6x)^2+(x^2-6x)-56=0
обозначим (x^2-6x) = T
получится квадратное уравнение
T^2 + T - 56 = 0
по т.Виета
T1*T2 = -56
T1 + T2 = -1
T1 = 7
T2 = -8
вернемся к х
x^2 - 6x = 7 ______ x^2 - 6x = -8
x^2 - 6x - 7 = 0 ___ x^2 - 6x + 8 = 0
x1*x2 = -7 _______ x3*x4 = 8
x1 + x2 = 6 ______ x3 + x4 = 6
x1 = 7 __________ x3 = 2
x2 = -1 _________ x4 = 4
Ответ: {-1; 2; 4; 7}
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Verified answer
обозначим (x^2-6x) = T
получится квадратное уравнение
T^2 + T - 56 = 0
по т.Виета
T1*T2 = -56
T1 + T2 = -1
T1 = 7
T2 = -8
вернемся к х
x^2 - 6x = 7 ______ x^2 - 6x = -8
x^2 - 6x - 7 = 0 ___ x^2 - 6x + 8 = 0
x1*x2 = -7 _______ x3*x4 = 8
x1 + x2 = 6 ______ x3 + x4 = 6
x1 = 7 __________ x3 = 2
x2 = -1 _________ x4 = 4
Ответ: {-1; 2; 4; 7}