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Fenika1010
@Fenika1010
July 2022
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Решите уравнение: (x+248)+(x+243)+(x+238)+…+(x+3)=6125.
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sedinalana
Verified answer
A1=x+248
a2=x+243
an=x+3
Sn=6125
d=a2-a1=x+243-x-248=-5
an=a1+(n-1)*d
x+248-5(n-1)=x+3
5(n-1)=x+248-x-3
5(n-1)=245
n-1=245:5
n-1=49
n=49+1
n=50
S50=(x+248+x+3)*50/2=61250
(2x+251)*25=6125
2x+251=6125:25
2x+251=245
2x=245-251
2x=-6
x=-3
2 votes
Thanks 6
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Answers & Comments
Verified answer
A1=x+248a2=x+243
an=x+3
Sn=6125
d=a2-a1=x+243-x-248=-5
an=a1+(n-1)*d
x+248-5(n-1)=x+3
5(n-1)=x+248-x-3
5(n-1)=245
n-1=245:5
n-1=49
n=49+1
n=50
S50=(x+248+x+3)*50/2=61250
(2x+251)*25=6125
2x+251=6125:25
2x+251=245
2x=245-251
2x=-6
x=-3