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prostochel37
@prostochel37
August 2022
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Решите уравнение (x+3)^2−3(x−1)^2=2(x+2)(2−x).
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Sadbitch32
X=1/6
x^2+6x+9-3(x^2-2x+1)=2(x+2)(2-x)
x^2+6x+9-3x^2+6x-3= 2(4-x^2)
-2x^2+12x+6=8-2x^2
12x+6=8
12x=2
x=1/6
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Answers & Comments
x^2+6x+9-3(x^2-2x+1)=2(x+2)(2-x)
x^2+6x+9-3x^2+6x-3= 2(4-x^2)
-2x^2+12x+6=8-2x^2
12x+6=8
12x=2
x=1/6