(x+7)(x-5)²=13(x-5)

(x+7)(x-5)²-13(x-5)=0

(х-5)((х+7)(х-5)-13)=0

(х-5)(х²-5х+7x-35-13)=0

(x-5)(x²+2x-48)=0

x-5=0

x=5

x²+2x-48=0

D=b²-4ac

D=2²-4×1×(-48)=4+192=√196=14

x1=-2-14/2 = -16/2 = -8

x2=-2+14/2 = 12/2 = 6

Ответ: x=5, x1=-8, x2=6