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Young25
@Young25
July 2022
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Решите уравнение:
x²(x+2)-(x+2)(x²-2x+4)=0
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мошкада
Решение по фото.........!...!.....!..
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vladimirputin5
X3+2x²-x3-2x²+4+2x²-4x+8=0
2x3+2x²+12=0
x(2
x²+2x)+12=0
1) x=0
2) 2
x²+2x+12=0
D=2
²-4*2*12=4-96=92≈√8
x1=-2²-√8=-4-√8=-4√8
x2=-4+√8=4√8
ответ x1=-4√8,x2=4√8
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Answers & Comments
2x3+2x²+12=0
x(2x²+2x)+12=0
1) x=0
2) 2x²+2x+12=0
D=2²-4*2*12=4-96=92≈√8
x1=-2²-√8=-4-√8=-4√8
x2=-4+√8=4√8
ответ x1=-4√8,x2=4√8