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Eliaromanova4
@Eliaromanova4
June 2022
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Решите уравнение: x*x+2*x-3=0
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isom
Х²+2х-3=0
Д=4-4(-3)=4+12=16
х₁=(-2-4)/2=-3
х₂=(-2+4)/2=1
1 votes
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Юрец123
По теореме Виета x1=1, x2=-3
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Answers & Comments
Д=4-4(-3)=4+12=16
х₁=(-2-4)/2=-3
х₂=(-2+4)/2=1