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sofia212000
@sofia212000
July 2022
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Решите уравнение
x+y=10
x^2+y^2=68
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Zhiraffe
Y=10-x, подставим во второе: x^2+(10-x)^2=68, раскроем: x^2+100-20x+x^2=68, значит 2*x^2-20x+32=0, разделим на два: x^2-10x+16=0. D=100-64=36=6^2. x1=(10+6)/2=8. x2=(10-6)/2=2. Соответственно, у1=10-8=2, у2=10-2=8. Ответ: (8;2), (2:8).
3 votes
Thanks 3
sofia212000
спасибо :3
Zhiraffe
На здоровье ))
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