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rusaz5555
@rusaz5555
August 2022
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решите уравнение y-6]-[y-4]=3y 8y-3-[y+7]=4 9p-[11p-15]=289 3[2x+4]-[x-2]=35+[x-6]
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anna1831
Y-6 - (y-4)=3y 8y-3-(y+7)=4 9p-(11p-15)=289
y-6-y+4-3y=0 8y-3-y-7-4=0 9p-11p+15-289=0
-3y=2 7y=14 -2p=274
y= - 2/3 y=2 p= - 137
3(2x+4)-(x-2)=35+(x-6)
6x+12-x+2= 35+x-6
5x+14-35-x+6=0
4x=15
x= 15/4 или 3 целые 3/4 или 3,75
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Answers & Comments
y-6-y+4-3y=0 8y-3-y-7-4=0 9p-11p+15-289=0
-3y=2 7y=14 -2p=274
y= - 2/3 y=2 p= - 137
3(2x+4)-(x-2)=35+(x-6)
6x+12-x+2= 35+x-6
5x+14-35-x+6=0
4x=15
x= 15/4 или 3 целые 3/4 или 3,75