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TKau
@TKau
July 2022
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Решите уравнение
y^3-2y^2=y-2
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chepyh
Y^3-2y^2-y+2=0
y(y^2-2y-1+2-2)=-2
y(y^2-2y+1-2)=-2
y(y-1)^2-2+2=0
y(y-1)^2=0
y=0 или y-1 = 0;
y2= 1;
Ответ: y = 1
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Answers & Comments
y(y^2-2y-1+2-2)=-2
y(y^2-2y+1-2)=-2
y(y-1)^2-2+2=0
y(y-1)^2=0
y=0 или y-1 = 0;
y2= 1;
Ответ: y = 1