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snikers200
@snikers200
June 2022
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решите уравнение
y^5-y^4+2y^2=3y-3+2y^3
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mathgenius
Y^4(y-1) -2y^2*(y-1)-3(y-1)=0
(y-1)(y^4-2y^2-3)=0
y1=1
y^4-2y^2-3=0
y^2=t>=0
t^2-2t-3=0
t1=3 y2=+-√3
t2=-1 не подх
Ответ:y1=1 y2,3=+-√3
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Answers & Comments
(y-1)(y^4-2y^2-3)=0
y1=1
y^4-2y^2-3=0
y^2=t>=0
t^2-2t-3=0
t1=3 y2=+-√3
t2=-1 не подх
Ответ:y1=1 y2,3=+-√3