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тюкалкатюктюк
@тюкалкатюктюк
August 2022
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решите уравнение
(20х+80х)•(300-10х)=400
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Dимасuk
Verified answer
(20x + 80x)(300 - 10x) = 400
100x(300 - 10x) = 400
x(300 - 10x) = 4
300x - 10x² = 4
150x - 5x² = 2
5x² - 150x + 2 = 0
D = 150² - 5·4·2 = 22500 - 40 = 22460 = (2√5615)²
x₁ = (150 + 2√5615)/10 = 15 + √5615/5
x₂ = (150 - 2√5615)/10 = 15 - √5615/5
Ответ: x = 15 - 0,2√5615; 15 + 0,2√5615.
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Thanks 2
sedinalana
(20х+80х)•(300-10х)=400
100x*(300-10x)=400
x(300-10x)=4
300x-10x
²-4=0
5x
²-150x+2=0
D=22500-40=22460
√D=2√5615
x1=(150-2
√5615)/10=15-0,5√5615
x2=15+0,5
√5615
0 votes
Thanks 0
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Answers & Comments
Verified answer
(20x + 80x)(300 - 10x) = 400100x(300 - 10x) = 400
x(300 - 10x) = 4
300x - 10x² = 4
150x - 5x² = 2
5x² - 150x + 2 = 0
D = 150² - 5·4·2 = 22500 - 40 = 22460 = (2√5615)²
x₁ = (150 + 2√5615)/10 = 15 + √5615/5
x₂ = (150 - 2√5615)/10 = 15 - √5615/5
Ответ: x = 15 - 0,2√5615; 15 + 0,2√5615.
100x*(300-10x)=400
x(300-10x)=4
300x-10x²-4=0
5x²-150x+2=0
D=22500-40=22460
√D=2√5615
x1=(150-2√5615)/10=15-0,5√5615
x2=15+0,5√5615