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nematdjanovna
@nematdjanovna
August 2022
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Решите уравнение:25^х-22*5^х-75=0
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AnonimusPro
Verified answer
25^x-22*5^x-75=0
5^(2x)-22*5^x-75=0
делаем замену:
y=5^x, y>0
y^2-22y-75=0
D=484+300=784=28^2
y1=(22+28)/2=25
y2=(22-28)/2<0 - не подходит
обратная замена:
5^x=25
x=2
Ответ: x=2
1 votes
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Answers & Comments
Verified answer
25^x-22*5^x-75=05^(2x)-22*5^x-75=0
делаем замену:
y=5^x, y>0
y^2-22y-75=0
D=484+300=784=28^2
y1=(22+28)/2=25
y2=(22-28)/2<0 - не подходит
обратная замена:
5^x=25
x=2
Ответ: x=2