решите уравнение:2x(x+1)=x^2-1
2x(x+1)=x^2-1
2x^2+2x=x^2-1
2x^2-x^2+2x+1=0
2+2x+1=0
2x=-2-1
2x=-3
x=-3/2
2х^2 + 2x = x^2 - 12x^2 - x^2 +2x + 1 = 0x^2 +2x + 1 = 0D = 4-4 = 0x= -2/2 = -1Ответ:-1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2x(x+1)=x^2-1
2x^2+2x=x^2-1
2x^2-x^2+2x+1=0
2+2x+1=0
2x=-2-1
2x=-3
x=-3/2
2х^2 + 2x = x^2 - 1
2x^2 - x^2 +2x + 1 = 0
x^2 +2x + 1 = 0
D = 4-4 = 0
x= -2/2 = -1
Ответ:-1