Решите уравнение.3х^2+8x-3=0
D=64-4*3*(-3)=100
x1= (-8+10)/6=1/3
x2= (-8-10)/6=-3
3x^2+8x-3=0
D=8^2-4*3*(-3)=64+36=√100=10
x1=(-8+10)/6=2/6=0.333
x2=(-8-10)/6=-3
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D=64-4*3*(-3)=100
x1= (-8+10)/6=1/3
x2= (-8-10)/6=-3
3x^2+8x-3=0
D=8^2-4*3*(-3)=64+36=√100=10
x1=(-8+10)/6=2/6=0.333
x2=(-8-10)/6=-3