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help248
@help248
July 2022
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Решите уравнение !!!!!!
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rubilovalex
5^(x^2-5x-6)=5^0; x^2-5x-6=0; D=(-5)^2-4*1*(-6)=25+24=49; x1=(5-7)/2; x2=(5+7)/2. x1= -1, x2=6. Ответ: x1= -1, x2=6.
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rubilovalex
1,5=3/2=(2/3)^-1. (2/3^-1)^5x-7=(2/3)^x+1; (2/3)^7-5x=(2/3)^x+1; 7-5x=x+1; -5x-x=1-7; -6x= -6; x=(-6)/(-6)=1. Ответ: x=1.
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