Ответ:
cos2x = 1
2x = +- arccos1 + 2Пn, n∈Z
2x = 0 + 2Пn, n∈Z
x = 2Пn/2, n∈Z
x = Пn, n∈Z
Ответ: x = Пn, n∈Z
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Ответ:
cos2x = 1
2x = +- arccos1 + 2Пn, n∈Z
2x = 0 + 2Пn, n∈Z
x = 2Пn/2, n∈Z
x = Пn, n∈Z
Ответ: x = Пn, n∈Z