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June 2022
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решите уравнение
k^2 + 5k + 6 = 0
k^2+4k+13=0
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MrHelper98
1)
k^2 + 5k + 6 = 0
Дискр.=25-4*1*6=1
к1=-5+1/2 к1=-2
к2=-5-1/2 к2=-3
2)
k^2+4k+13=0
дискр = 16-4*1*13=-36 <0 корней нет
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Answers & Comments
Дискр.=25-4*1*6=1
к1=-5+1/2 к1=-2
к2=-5-1/2 к2=-3
2)k^2+4k+13=0
дискр = 16-4*1*13=-36 <0 корней нет