решите уравнение |sin2x|=cosx
|2sinxcosx|=cosx
1) cos x = 0
x=pi/2 + pi*k, k in Integers
2) 2|sin x|=1
4sin^2 x=1
2(1+cos 2x)=1
cos 2x = -1/2
2x = +- 2pi/3 + 2pin
x = +- pi/3 + pi*n, n in Integers
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
|2sinxcosx|=cosx
1) cos x = 0
x=pi/2 + pi*k, k in Integers
2) 2|sin x|=1
4sin^2 x=1
2(1+cos 2x)=1
cos 2x = -1/2
2x = +- 2pi/3 + 2pin
x = +- pi/3 + pi*n, n in Integers