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KekuS322
@KekuS322
July 2022
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Решите уравнение:(x-2)(x^2+2x+1)=4(x+1)
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yellok
Verified answer
(x-2)(x²+2x+1)=4(x+1)
(x-2)(x+1)²-4(x+1)=0
(x+1)((x-2)(x+1)-4))=0 ⇒ x+1=0 или
(x-2)(x+1)-4)=0
⇒x=-1 или x²-x-6=0
D=1+4*6=25
x(1)=(1+5)/2=3
x(2)=(1-5)/2=-2
ответ: x= -1, x= -2, x=3
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Answers & Comments
Verified answer
(x-2)(x²+2x+1)=4(x+1)(x-2)(x+1)²-4(x+1)=0
(x+1)((x-2)(x+1)-4))=0 ⇒ x+1=0 или (x-2)(x+1)-4)=0 ⇒x=-1 или x²-x-6=0
D=1+4*6=25
x(1)=(1+5)/2=3
x(2)=(1-5)/2=-2
ответ: x= -1, x= -2, x=3