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dok344
@dok344
July 2022
2
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Решите уравнение
x3
=
x2
+6x
.
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ArukaJ00
Х3-х2-6х=0
х(х2-х-6)=0
х=0 или х2-х-6=0
Д=1+24=25
х1=(1+5)/2=3
х2=(1-5)/2=-2
8 votes
Thanks 24
dok344
так же получилось
ArukaJ00
ну вот
guzal2997
Переносим с правой части в левую и выносим х за скобку
х^3-x^2 -6x=0
x(x^2-x-6)=0
x=0 или x^2-x-6=0
D=1+4*6=25
x1=(1-5)/2= -2
x2=(1+5)/2= 3
5 votes
Thanks 5
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Answers & Comments
х(х2-х-6)=0
х=0 или х2-х-6=0
Д=1+24=25
х1=(1+5)/2=3
х2=(1-5)/2=-2
х^3-x^2 -6x=0
x(x^2-x-6)=0
x=0 или x^2-x-6=0
D=1+4*6=25
x1=(1-5)/2= -2
x2=(1+5)/2= 3