Решите уравнения: 1) 36x^2 + 12x + 1 = 0 (через дискриминант) 2) 5x^2 - 8x

August 2022 2 19 Report

Решите уравнения:
1) 36x^2 + 12x + 1 = 0 (через дискриминант)
2) 5x^2 - 8x - 4 = 0(через чётный коэффициент)

Shuna2000 $1)\; \; 36x^2+12x+1=0\\\\D=b^2-4ac=12^2-4\cdot 36\cdot 1=0\\\\x= \frac{-12\pm 0}{2\cdot 36}=- \frac{1}{6}\\\\2)\; \; 5x^2-8x-4=0\\\\\frac{D}{4}=(\frac{b}{2})^2-ac=4^2+5\cdot 4=36\\\\x_{1,2}=\frac{4\pm 6}{5}\\\\x_1=-\frac{2}{5}=0,4\; \; ,\; \; x_2=\frac{10}{5}=2$

1 votes Thanks 3

NNNLLL54

Verified answer

Первое
36х^2+12х+1=0
д=√12^2-4•36•1=√144-144= 0
х1,2= -12±0/2•36
х1=-12+0/72=-12/72
х2=-12-0/72
ответ:х1,2= -12/72
вроде так

1 votes Thanks 3

Answers & Comments

Verified answer

vychislite 4 26 43 108 12

vypolnite vozvedenie v kvadrat 1 04x 15y 2 x y 3 ab c1

1 reshite uravnenie 7m 13 9m19 0 2 razlozhite na mnozhiteli x6 z

reshite uravneniya 1 6x2 12x 0 2 6x2 12x 0 3 6x2 12 0 4 49x2

reshite 1 3aa2 a3 2 3y 1 6y 3 4ab 2a b

8a b 5a 8 6ab c 7a b15c18 8125cd 0008b

uprostite vyrazhenie 1 a bababb 2 y 3y3y9 yy 3y3 y3

razlozhite na mnozhiteli mnogochlen 1 x 3x 4x 12 2 s6 10c 5c 5

v pervom vagone elektropoezda ehalo v 6 raz bolshe passazhirov chem vo vtorom kog

reshite sistemu uravnenij 2x y 1 5x 2y 0

рекомендуемые вопросы

Helpful Links

Helpful Social