решите уравнения 2 плииз 4^(x+1)=64^(x-1)
2^(x+3)-2^(x+1)=12
1)4^(x+1)=64^(x-1)
нет решений
2)2^(x+3)-2^(x+1)=12
2^(х+3)-2^(х+1)=3*2^(х+1)
3*2^(х+1)=2^2*3
2^(х+3)-2^(х+1)-12=0
x=1
4^(x+1)=4^(3(x-1))
x+1=3(x-1)
3x-3-x-1=0
2x-4=0
2x=4
х=2
2^x*2^3-2^x*2=12
2^x(2^3-2)=12
2^x=2
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Answers & Comments
1)4^(x+1)=64^(x-1)
нет решений
2)2^(x+3)-2^(x+1)=12
2^(х+3)-2^(х+1)=3*2^(х+1)
3*2^(х+1)=2^2*3
2^(х+3)-2^(х+1)-12=0
x=1
4^(x+1)=4^(3(x-1))
x+1=3(x-1)
3x-3-x-1=0
2x-4=0
2x=4
х=2
2^x*2^3-2^x*2=12
2^x(2^3-2)=12
2^x=2
x=1