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lobanova2003160
@lobanova2003160
June 2022
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Решите уравнения 2.4х-х^2=0;64х-х^3
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Lyudaxbm89
2,4x-x^2=0
x(2,4-x)=0
x=0 2,4-x=0
x=2,4
Во втором уравнении не написано,чему равно,но если там 0, то:
64x-x^3=0
x(64-x^2)=0
x=0 64-x^2=0
(8-x)(x+x)=0
x=8 x=-8
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Answers & Comments
x(2,4-x)=0
x=0 2,4-x=0
x=2,4
Во втором уравнении не написано,чему равно,но если там 0, то:
64x-x^3=0
x(64-x^2)=0
x=0 64-x^2=0
(8-x)(x+x)=0
x=8 x=-8