Решите уравнения: 8.40. Created by pirogowalexander. algebra-ru

(3x-1)²+(x+3)²=209x²-6x+1+x²+6x+9=209x²+x²+10=2010x²=20-1010x²=10x²=1x=(3x+2)³-(3x-2)³=12427x³+54x²+36x+8-(27x³-54x²+36x-8)=12427x³+54x²+36x+8-27x³+54x²-36x+8=12454x²+8+54x²+8=124108x²+16=124108x²=124-16108x²=108x²=1x=(5x+2)²+(x-10)²=20825x²+20x+4+x²-20x+100=20825x²+x²+104=20826x²=208-10426x²=104x²=4x=(2x+1)³-(2x-1)³=2188x³+12x²+6x+1-(8x³-12x²+6x-1)=2188x³+12x²+6x+1-8x³+12x²-6x+1=21812x²+1+12x²+1=21824x²+2=21824x²=218-224x²=216x²=9x=

Решите уравнения: 8.40...

pirogowalexander @pirogowalexander

September 2021 1 19 Report

Решите уравнения: 8.40

Answers & Comments

NiGhtWolFs (3x-1)²+(x+3)²=20
9x²-6x+1+x²+6x+9=20
9x²+x²+10=20
10x²=20-10
10x²=10
x²=1
x= $б1$

(3x+2)³-(3x-2)³=124
27x³+54x²+36x+8-(27x³-54x²+36x-8)=124
27x³+54x²+36x+8-27x³+54x²-36x+8=124
54x²+8+54x²+8=124
108x²+16=124
108x²=124-16
108x²=108
x²=1
x= $б1$

(5x+2)²+(x-10)²=208
25x²+20x+4+x²-20x+100=208
25x²+x²+104=208
26x²=208-104
26x²=104
x²=4
x= $б2$

(2x+1)³-(2x-1)³=218
8x³+12x²+6x+1-(8x³-12x²+6x-1)=218
8x³+12x²+6x+1-8x³+12x²-6x+1=218
12x²+1+12x²+1=218
24x²+2=218
24x²=218-2
24x²=216
x²=9
x= $б3$

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