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Шококомококо
@Шококомококо
July 2022
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решите уравнения: a) (2x-5)^2-(2x-3)(2x+3)=0 б) 9y^2-25=0
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zhenyaM2002
Verified answer
(2x - 5)² - (2x + 3)(2x - 3) = 0
(2x) ² - 2*2x*5 + 5² - ( (2x)² - 3² ) = 0
4x² - 20x + 25 - 4x² + 9 = 0
-20x + 34 = 0
-20x = - 34
x = (-34) : ( -20)
х = - 1,7
9у² - 25 = 0
(3у)² - 5² = 0
(3у - 5)(3у + 5) =0
произведение = 0, если один из множителей =0
3у - 5 = 0
3у=5
у= 5 : 3
у₁ = 1 ²/₃
3у + 5 =0
3у = - 5
у₂ = - 1 ²/₃
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Answers & Comments
Verified answer
(2x - 5)² - (2x + 3)(2x - 3) = 0(2x) ² - 2*2x*5 + 5² - ( (2x)² - 3² ) = 0
4x² - 20x + 25 - 4x² + 9 = 0
-20x + 34 = 0
-20x = - 34
x = (-34) : ( -20)
х = - 1,7
9у² - 25 = 0
(3у)² - 5² = 0
(3у - 5)(3у + 5) =0
произведение = 0, если один из множителей =0
3у - 5 = 0
3у=5
у= 5 : 3
у₁ = 1 ²/₃
3у + 5 =0
3у = - 5
у₂ = - 1 ²/₃