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Agata045
@Agata045
July 2022
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Решите уравнения. А) (Х+3)^2 -2 (х+3)-8=0
Б) 3^х+3^х-3=12
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sedinalana
Verified answer
A
x+3=a
a²-2a-8=0
a1+a2=2 U a1*a2=-8
a1=-2⇒x+3=-2⇒x=-5
a2=4⇒x+3=4⇒x=1
Б
3^(x-3)*(27+1)=12
3^(x-3)*28=12
3^(x-3)=3/7
x-3=log(3)(3/7)
x=3+1-log(3)7
x=4-log(3)7
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Книгоlove
Х²+6х+9-2х-6-8=0
х²+4х-5=0
(x+5)(x-1)=0
x1=-5 x2=1
0 votes
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Answers & Comments
Verified answer
Ax+3=a
a²-2a-8=0
a1+a2=2 U a1*a2=-8
a1=-2⇒x+3=-2⇒x=-5
a2=4⇒x+3=4⇒x=1
Б
3^(x-3)*(27+1)=12
3^(x-3)*28=12
3^(x-3)=3/7
x-3=log(3)(3/7)
x=3+1-log(3)7
x=4-log(3)7
х²+4х-5=0
(x+5)(x-1)=0
x1=-5 x2=1