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RTAKZM
@RTAKZM
July 2022
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Решите уравнения: а)Х^2+5х+24=0, б)-4х^2+19х-12=0, в)25х^2-10х+1=0, г)3х^2-5х+3=0
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l134679
А) D=b^2-4ac= 5^2-4*1*24=25-96 ----> Нет решения, т.к. D<0
b) -4x^2+19x-12=0/-1 ----> 4x^2-19+12 ----> D=b^2-4ac=(-19)^2-4*4*12=361-192=169 ----> x1/2= -b+-√D/2a= 19+-√169/2*4=19+-13/8 -----> x1=19+13/8=4; x2=19-13/8=0.75
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Answers & Comments
b) -4x^2+19x-12=0/-1 ----> 4x^2-19+12 ----> D=b^2-4ac=(-19)^2-4*4*12=361-192=169 ----> x1/2= -b+-√D/2a= 19+-√169/2*4=19+-13/8 -----> x1=19+13/8=4; x2=19-13/8=0.75