Решите уравнения: Х^2-х-72=0 -4в^2+7в-3=0. Created by annaglazkova2. algebra-ru

D=b^2-4ac=(-1)^2-4*1*(-72)=1+288==17х1=х2=Ответ: -8 и 9D=b^2-4ac=7^2-4*(-4)*(-3)=49-48=х1=х2=

Решите уравнения: Х^2-х-72=0 -4в^2+7в-3=0...

July 2022 1 6 Report

Решите уравнения:
Х^2-х-72=0

-4в^2+7в-3=0

Answers & Comments

Boоmhauer D=b^2-4ac=(-1)^2-4*1*(-72)=1+288= $\sqrt{289}$ =17
х1= $\frac{-b- \sqrt{D} }{2a} = \frac{1-17}{2} = \frac{-16}{2} =-8
$
х2= $\frac{-b+ \sqrt{D} }{2a} = \frac{1+17}{2} = \frac{18}{2} = 9$
Ответ: -8 и 9

D=b^2-4ac=7^2-4*(-4)*(-3)=49-48= $\sqrt{1} =1$
х1= $\frac{-b- \sqrt{D} }{2a} = \frac{-7-1}{2*(-4)} = \frac{-8}{-8} =1$
х2= $\frac{-b+ \sqrt{D} }{2a} = \frac{-7+1}{(-8)} = \frac{-6}{-8} =0,75$

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