Решите уравнения пожалуйста. Пробовала, никак не выходит.
(x-1)(x^2+8x+16)=6(x+4)
x^3-3x^2-x+3=0
(x-1)(x^2+8x+16)=6(x+4)
x^3-3x^2-x+3=0
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Answers & Comments
x^3 - 3x^2 - x + 3 = 0
x^2(x - 3) - 1*(x - 3) = 0
(x^2 - 1) (x - 3) =0
x^2 - 1 = 0
x^2 = 1
x= ± 1
x - 3 = 0
x = 3
2) --------------------------------------------------
(x - 1) (x^2 + 8x + 16) = 6 (x+ 4)
(x - 1) ( x + 4) ( x + 4) = 6(x + 4)
(x - 1) (x + 4)^2 - 6(x + 4) = 0
(x + 4)* ( (x - 1)(x + 4) - 6) = 0
(x + 4) ( x^2 + 4x - x - 4 - 6) = 0
(x + 4) ( x^2 + 3x - 10) = 0
(x + 4) (x + 5) (x - 2) = 0
x + 4 = 0
x1 = - 4 ;
x + 5 = 0
x2 = - 5;
x - 2 = 0
x3 = 2;
Verified answer
Первый -во вложении.