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gizon
@gizon
August 2021
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krugly1981
√3x² + 3x - 7 = 2x - 1
3x² + 3x - 7 = ( 2x - 1)²
3x² + 3x - 7 = ( 2x - 1)( 2x - 1)
3x² + 3x - 7 = 4x² - 4x + 1
3x² + 3x - 7 - 4x² + 4x - 1 = 0
- x² + 7x - 8 = 0
x² - 7x + 8 =0
D = b²- 4ac = (-7)² - 4 × 1 × 8 = 49 - 32 = 17
x1,2 = 7 +/-√17 / 2
( x - 3) / (7 + x) = 1/9
9( x - 3) = 7 + x
9x - 27 = 7 + x
9x - x = 27 + 7
8x = 34
x = 34/8
x = 4,25
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Answers & Comments
3x² + 3x - 7 = ( 2x - 1)²
3x² + 3x - 7 = ( 2x - 1)( 2x - 1)
3x² + 3x - 7 = 4x² - 4x + 1
3x² + 3x - 7 - 4x² + 4x - 1 = 0
- x² + 7x - 8 = 0
x² - 7x + 8 =0
D = b²- 4ac = (-7)² - 4 × 1 × 8 = 49 - 32 = 17
x1,2 = 7 +/-√17 / 2
( x - 3) / (7 + x) = 1/9
9( x - 3) = 7 + x
9x - 27 = 7 + x
9x - x = 27 + 7
8x = 34
x = 34/8
x = 4,25