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Banana06
@Banana06
July 2022
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решите уравнения (x-1)(2x+6)=0; x²-16=0
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Anna56512
1.(x-1)(2x+6)=0
x-1=0 или 2x+6=0
x=1 2(x+3)=0
x+3=0
x=-3
2. x²-16=0
(x-4)(x+4)=0
x-4=0 или x+4=0
x=4 x=-4
6 votes
Thanks 8
HarutyunyanNane2001
1.2x^2+6x-2x-6=0
2x^2+4x-6=0/2
x^2+2x-3=0
D=b^2-4ac=4-4*(-3)=16=4^2
x1=-2+4/2=1
x2=-2-4/2=-3
2.x^2-16=0
(x+4)(x-4)=o
x=-4
x=4
1 votes
Thanks 1
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Answers & Comments
x-1=0 или 2x+6=0
x=1 2(x+3)=0
x+3=0
x=-3
2. x²-16=0
(x-4)(x+4)=0
x-4=0 или x+4=0
x=4 x=-4
2x^2+4x-6=0/2
x^2+2x-3=0
D=b^2-4ac=4-4*(-3)=16=4^2
x1=-2+4/2=1
x2=-2-4/2=-3
2.x^2-16=0
(x+4)(x-4)=o
x=-4
x=4