Решите уравнения √(x^2+2)+√(x^3+x^2)=0 √(4x+2+2(3x^2+4))=x+2. Created by Susanna123. algebra-ru

Решите уравнения √(x^2+2)+√(x^3+x^2)=0 √(4x+2+2(3x^2+4))=x+2...

August 2022 1 4 Report

Решите уравнения
√(x^2+2)+√(x^3+x^2)=0
√(4x+2+2(3x^2+4))=x+2

Answers & Comments

0Dizaster0 √(x^2+2)+√(x^3+x^2)=0
[x^2+2=o
x^3+x^2=o. x^2(x+1)=0
[x=0
x=-1

√(4x+2+2(3x^2+4))=x+2
[x+2>0
4x+2+6x^2+8-x^2-4x-4=0
[x>-2
5x^2=-6. Пустое множество.

0 votes Thanks 0

Susanna123 Спасибо, конечно, но это неправильное решение)))

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Susanna123 July 2022 | 0 Ответы

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