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sveta16081976
@sveta16081976
August 2022
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решите уравнения x^3 - 3x^2 - 4x + 12 = 0
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Kixcertborn2
Verified answer
X^3 - 3x^2 - 4x + 12 = 0
x^2*(x-3)-4(x-3)=0
(x^2-4)*(x-3)=0
(x-2)*(x+2)(x-3)=0
x-2=0 x=2
x+2=0 x=-2
x-3=0 x=3
Otvet:
x1=2
x2=-2
x3=3
3 votes
Thanks 12
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Answers & Comments
Verified answer
X^3 - 3x^2 - 4x + 12 = 0x^2*(x-3)-4(x-3)=0
(x^2-4)*(x-3)=0
(x-2)*(x+2)(x-3)=0
x-2=0 x=2
x+2=0 x=-2
x-3=0 x=3
Otvet:
x1=2
x2=-2
x3=3