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olyaefimova00
@olyaefimova00
July 2022
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Решите уравнения:1) (2x-1)²=2x-1; 2) (x-3)²=4(x-3); 3) 4(x-3)²=(2x+6)²; 4) (3x+4)²=3(x+4)
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ainura20041701
1)(2х-1)^2=2х-1
4х^2-4х+1=2х-1
4х^2-4х+1-2х+1=0
4х^2-6х+2=0
Х-1=0
2х-1=0
Х=1
Х=1/2
Х1=1/2,х2=1
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Answers & Comments
4х^2-4х+1=2х-1
4х^2-4х+1-2х+1=0
4х^2-6х+2=0
Х-1=0
2х-1=0
Х=1
Х=1/2
Х1=1/2,х2=1