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Herf
@Herf
August 2022
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Решите уравнения:
а) log7 (3x-5) - log7 (9-2x) = 1
б) 4 - lg^2 x = 3lg x
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passion03
B) lgx=y, y>0
-y^2-3y+4=0 *-1
y^2+3y-4=0
D=25
y1=1 y2=-4(net rew)
lgx=1
x=1
1 votes
Thanks 9
passion03
log7(3x-5)-log7(9-2x)=log7(7)
passion03
(3x-5)/(9-2x)=7 rewai dal'we
nikasun173
Одз:
Х=5/3
Х=4.5
_________________
Решение:
Log7(3x-5)=log7(9-2x)
3x-5=9-2x
3x+2x=9+5
5x=14
x=2.8
Ответ: х=2,8
2 votes
Thanks 6
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Answers & Comments
-y^2-3y+4=0 *-1
y^2+3y-4=0
D=25
y1=1 y2=-4(net rew)
lgx=1
x=1
Х=5/3
Х=4.5
_________________
Решение:
Log7(3x-5)=log7(9-2x)
3x-5=9-2x
3x+2x=9+5
5x=14
x=2.8
Ответ: х=2,8