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grizzlykov
@grizzlykov
March 2022
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sedinalana
1
x(x+16)(√x-2)(x+6)(x-4)=0
x∈[0;∞)
x=0
x+16=0⇒x=-16 не удов усл
√х-2=0⇒√х=2⇒х=4
х+6=0⇒х=-6 не удов усл
х-4=0⇒х=4
ответ x={0;4}
2
домножим на 20
5(3x²+5x)-4(7-2x)=2(3x²+7)
15x²+25x-28+8x-6x²-14=0
9x²+33x-42=0
D=1089+1512=2601
x1=(-33-51)/18=-14/3
x2=(-33+51)/18=1
2 votes
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Answers & Comments
x(x+16)(√x-2)(x+6)(x-4)=0
x∈[0;∞)
x=0
x+16=0⇒x=-16 не удов усл
√х-2=0⇒√х=2⇒х=4
х+6=0⇒х=-6 не удов усл
х-4=0⇒х=4
ответ x={0;4}
2
домножим на 20
5(3x²+5x)-4(7-2x)=2(3x²+7)
15x²+25x-28+8x-6x²-14=0
9x²+33x-42=0
D=1089+1512=2601
x1=(-33-51)/18=-14/3
x2=(-33+51)/18=1