N1

3^(3x + 4) = 3

3x + 4 = 1

3x = -3

x = -1

N2

log 3 (2x - 3) = 2

log 3 (2x - 3) = log 3 (9)

2x - 3 = 9

2x = 12

x = 6

N3

log 3 (x + 3) + log 3 (3) = log 3 (6)

log 3 (3x + 9) = log 3 (6)

3x + 9 = 6

3x = -3

x = -1

Ответ:

1)x=-1

2)x=6

3)x=-1

Объяснение:

1)3x+4=1

3x=-3

x=-1

2) log3(2x-3)=2

log3(2x-3)=log3(9)

2x-3=9

2x=9+3

2x=12

x=6

3)log3(x+3)+log3(3)=log3(6)

Log3(3(x+3))=log3(6)

3x+9=6

3x=6-9

3x=-3

x=-1