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Betmen1
@Betmen1
July 2022
2
12
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Решите уравнения
(х-12)(3х+9)=0
(х+2)² = 0
х² - 25= 0
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Roceteerr
1)х=12;-3
2)х=-2
3)х=+5;-5
0 votes
Thanks 0
Betmen1
Мне нужно решение
Roceteerr
1) (х-12)(3х+9) это выражение равно нулю ,если (х-12)=0 или (3х+9)=0
х=12 3х=-9
х=-3
2)(х+2)^2=0 (х+2)(х+2)=0 аналогично х+2=0 х=-2
Roceteerr
3) х= корень из 25 х=+-5
Ksenon4ik
Вот тебе и решение))
2 votes
Thanks 3
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Answers & Comments
2)х=-2
3)х=+5;-5
х=12 3х=-9
х=-3
2)(х+2)^2=0 (х+2)(х+2)=0 аналогично х+2=0 х=-2