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umnikuz1
@umnikuz1
July 2022
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Решите уровнения Пжжжжжж
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antonviktorov
1) 3 x^{2} = 0;
x^{2} = 0;
x = 0
2) (x + 1)(x-1) = 0;
x = 1
x = - 1
3)4 x^{2} - 1 = 0
(2x + 1)(2x - 1) = 0
x = 0.5
x = -0.5
4)3x^{2} = 5x
frac{3}{5} x = 1;
x = frac{5}{3} .
5)4x^{2} -4x+1=0
(2x - 1)^{2} = 0;
2x = 1;
x = 0.5.
6) x^{2} -16x-17 = 0;
x^{2} - 1 - 16x - 16 = 0;
(x+1)(x-1) - 16(x + 1) = 0;
(x+1)(x-1-16)=0
x=-1
x=17
7)0.3x² + 5x = 2
0.3x²+5x-2=0
0.3x²+3x+2-2x=0
хз
8)x² - 4x + 5 = 0
(x - 2)² = -1
невозможно
0 votes
Thanks 2
umnikuz1
огромное спс
antonviktorov
frac - это дробь
antonviktorov
x^{2} - x в квадрате
umnikuz1
ок
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Answers & Comments
x^{2} = 0;
x = 0
2) (x + 1)(x-1) = 0;
x = 1
x = - 1
3)4 x^{2} - 1 = 0
(2x + 1)(2x - 1) = 0
x = 0.5
x = -0.5
4)3x^{2} = 5x
frac{3}{5} x = 1;
x = frac{5}{3} .
5)4x^{2} -4x+1=0
(2x - 1)^{2} = 0;
2x = 1;
x = 0.5.
6) x^{2} -16x-17 = 0;
x^{2} - 1 - 16x - 16 = 0;
(x+1)(x-1) - 16(x + 1) = 0;
(x+1)(x-1-16)=0
x=-1
x=17
7)0.3x² + 5x = 2
0.3x²+5x-2=0
0.3x²+3x+2-2x=0
хз
8)x² - 4x + 5 = 0
(x - 2)² = -1
невозможно