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PW2033
@PW2033
August 2022
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Решите вот это:
а)3(х+4)-2(х-3)=24
б)2х^2-3х+1=0
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anastasiyasotn1
А) 3(х+4)-2(х-3)=24
3х+12-2х+6=24
3х-2х=24-12-6
х=6
1 votes
Thanks 1
makasimkas
А) 3x+12-2x+6=24
3x-2x=24-12-6
x=6
b) 2x^2-3x+1=0
D= (-3)^2-4*2*1=9-8=1
x1=1
x2=1/2
1 votes
Thanks 1
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Answers & Comments
3х+12-2х+6=24
3х-2х=24-12-6
х=6
3x-2x=24-12-6
x=6
b) 2x^2-3x+1=0
D= (-3)^2-4*2*1=9-8=1
x1=1
x2=1/2