Решите все плез!!! . Created by MadAngel555. algebra-ru

Решите все плез!!! ...

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$\frac{x}{\sqrt5}=\frac{x\sqrt5}{5}\\\\\frac{a}{b\sqrt{b}}=\frac{a\sqrt{b}}{b^2}\\\\\frac{3}{\sqrt{b}}=\frac{3\sqrt{b}}{b}\\\\\frac{2}{7\sqrt{y}}=\frac{2\sqrt{y}}{7y}\\\\\frac{4}{\sqrt{a+b}}=\frac{4\sqrt{a+b}}{a+b}\\\\\frac{1}{\sqrt{a-b}}=\frac{\sqrt{a-b}}{a-b}$

$\frac{5}{2\sqrt3}=\frac{5\sqrt3}{6}\\\\\frac{8}{3\sqrt2}=\frac{8\sqrt2}{6}\\\\\frac{3\sqrt5}{5\sqrt2}=\frac{3\sqrt{10}}{10}$

2 votes Thanks 1

rahlenko007

\frac{x}{√5} = \frac{x * \frac{x * √5}{5}

просто єкпериментировал сори

1 votes Thanks 0

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