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artyomya1
@artyomya1
August 2022
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решите ВСЕГО одно дифференциальное уравнение
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армения20171
Y'=3y²/(x²+1)
dy/dx=3y²/(x²+1)
dy/(3y²)=dx/(x²+1)
1/3*dy/y²=dx/(x²+1)
1/3*y^(-2+1)*1/(-2+1)=
arctgx+C
-1/3*1/y=arctgx+C
y=-1/(3arctgx+C)
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Answers & Comments
dy/dx=3y²/(x²+1)
dy/(3y²)=dx/(x²+1)
1/3*dy/y²=dx/(x²+1)
1/3*y^(-2+1)*1/(-2+1)=
arctgx+C
-1/3*1/y=arctgx+C
y=-1/(3arctgx+C)