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desint235
@desint235
July 2022
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.Решите задачу: Найдите массовые доли элементов в С2Н6.
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azubareva02
W(C) = Ar(C)/Mr(C2H6)
w(H) = Ar(H)/Mr(C2H6)
w(C)= 12*2/30 * 100% = 80%
w(H) = 6*1/30 * 100% = 20%
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Answers & Comments
w(H) = Ar(H)/Mr(C2H6)
w(C)= 12*2/30 * 100% = 80%
w(H) = 6*1/30 * 100% = 20%