F = kx
0.5 см = 5•10^-3 м
1)k = F1/x1 = 200/5•10^-3 = 40•10³ = 4•10⁴ Н/м
2)x2 = F2/k = 700/4•10⁴ = 175 • 10^-4 м = 175•10^-2 см = 1.75 см
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F = kx
0.5 см = 5•10^-3 м
1)k = F1/x1 = 200/5•10^-3 = 40•10³ = 4•10⁴ Н/м
2)x2 = F2/k = 700/4•10⁴ = 175 • 10^-4 м = 175•10^-2 см = 1.75 см