Ответ:
40 Ом
Объяснение:
I = U/R = U/ = 220/sqrt(Ra^2+30^2) = 220/sqrt(Ra^2+900)
sqrt(Ra^2+900) = 220/I
sqrt(Ra^2+900) = 50
Ra^2+900 = 2500
Ra^2 = 2500-900 = 1600
Ra = 40 Ом
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Ответ:
40 Ом
Объяснение:
I = U/R = U/ = 220/sqrt(Ra^2+30^2) = 220/sqrt(Ra^2+900)
sqrt(Ra^2+900) = 220/I
sqrt(Ra^2+900) = 50
Ra^2+900 = 2500
Ra^2 = 2500-900 = 1600
Ra = 40 Ом